[Ti] 400>500
Dave Friesen
davefriesen at mac.com
Tue Jan 7 09:06:58 PST 2003
Holy crap! I didn't know that overclocking my Ti required statistical analysis. Good thing I can't do math or I may have never attempted it. ;-)
But like I said previously, I practiced and practiced on a scrap board until I felt that I could remove surface mount resistors with a minimum of heat and time applied. All it takes is a second or two and the solder is relaxed enough that the resistor can be popped off.
Because I worked from instructions from knowledgeable people, practiced first and was careful in the actual operation I felt that my odds were very good, numbers be damned... ;-)
Regardless a 500Mhz machine is only going to be practical for a while longer, sooner or later it too will be replaced. Alas, upgrading is a known variable.
On Monday, January 06, 2003, at 03:15PM, Paul Russell <prussell at arc-software.com> wrote:
>You're right up to a point. It's not cost effective to test
>individual chips. though, so typically a small sample from each batch
>is tested. If the testing of the sample indicates that the entire
>batch may not be good at 500 MHz then the whole batch might get sold
>as 400 Mhz chips. However this is quite a conservative method and it
>may well be that say 90% of the chips are perfectly good at 500 Mhz
>or greater. Of course in the worst case scenario then perhaps only a
>small percentage might be good at 500 MHz, but then due to the nature
>of statistical distributions this would probably also indicate more
>serious problems, i.e. that the production process was in a pretty
>bad state. Like everything in life, it's a gamble - you need to do a
>quick bit of analysis before you do the over-clocking, e.g.
>
> BLOW UP YOUR MAC MAC WORKS FINE
>
> DO THE OVERCLOCKING -1000 +10
>
> DON'T DO IT !!! (shouldn't happen !) 0
>
>
>You also need a value of p, the probability of blowing up your Mac if
>you do the overclocking. Let's say that for a skilled electronics
>technician p = 0.001, while for an accident prone hobbyist it might
>be p = 0.5. In the case of the former it's probably worth taking the
>risk, in the case fo the latter: probably not. (But you knew that
>already ;-)).
>
>Paul
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