[X-Unix] Bash scripting help

[Russell McGaha]

Philip;
	THANKS for the mini tutorial; your info on command substitution  
helped with the last problem I was having.

THANKS again;
Russell

On Nov 8, 2005, at 11:56 AM, Philip J Robar wrote:

>
> On Nov 8, 2005, at 8:02 AM, Russell McGaha wrote:
>
>> I'm trying to check if a process is running before continuing my  
>> script
>> (BTW I'm a relative new-be at shell scripting); here's what I've  
>> tried:
>
> http://www.shelldorado.com
>
> and
>
> Advanced Bash-Scripting Guide by Medel Cooper at <http:// 
> www.tldp.org/LDP/abs/html/>
>
> are good places to look for shell scripting help.
>
> Here's my version of your script.
>
> Phil
>
>
> #!/bin/bash
>
> FileMaker="";
> let loop=0;													# Could also be ((loop = 0)), or let "loop  
> = 0"
>
> echo "Start"
>
> # "[[" is an extended form of test. It lets "&&" behave as you  
> expected it to.
> # '<' seems like it should have worked since it's within double  
> parentheses,
> # but "-lt" definitely gives the expected numerical result.
>
> while [[ "$Filemaker" == "" && ((loop -lt 10)) ]]; do		# "$loop"  
> within double parentheses is incorrect.
>
> 	# Command Substitution, "$(some command)" - replaces "$(some  
> command)" with output of the command.
> 	# Normally one would use some form of ps(1) in this situation.
> 	# foo(someNumber) refers to the "foo" command in section  
> "someNumber" of the man pages.
>
> 	Filemaker=$(top -l1 | grep "FileMaker")
> 	echo "Filemaker = " $Filemaker
>
> 	let loop++												# Could also be ((loop++))
> 	echo $loop
>
> done
>
> echo "stopping"
>
> exit 0
>
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