[X4U] Command to get permissions of a single item?

[Brett Conlon]

I usually use "ls -la" to show permissions on a whole folder. Here's what 
the man page on ls has to say about -l

The Long Format
     If the -l option is given, the following information is displayed for
     each file: file mode, number of links, owner name, group name, number 
of
     bytes in the file, abbreviated month, day-of-month file was last 
modi-
     fied, hour file last modified, minute file last modified, and the 
path-
     name.  In addition, for each directory whose contents are displayed, 
the
     total number of 512-byte blocks used by the files in the directory is
     displayed on a line by itself immediately before the information for 
the
     files in the directory.  If the file or directory has extended 
security
     information, the permissions field printed by the -l option is 
followed
     by a '+' character.

The "a" operand shows .hidden files too - kinda like show all.

But you said you wanted permissions for a single file... Doug's suggestion 
is correct, include it with the command:

ls -l /path_to_file

Coj




Doug McNutt <douglist at macnauchtan.com> 
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31/10/06 12:56 PM
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Re: [X4U] Command to get permissions of a single item?






At 20:29 -0400 10/30/06, Jerry Krinock wrote:
> The only command I can find for reading permissions is "ls",
>but of course that gives it for ITEMS IN the subject, which must be a
>directory.

I think you'll find that ls will return data for a single file if it is 
offered as the argument without any wild cards.

If you're looking for permissions of a directory then use the -d option.
-- 

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